
Section 7. Installation
272
Inputfrequencytorunningaverage(normalizedfrequency)=100/250
=0.4
Sin(0.4π)/(0.4π)=0.757(orreadfromfigureRunning‐Average
FrequencyResponse
(p.273),wheretheXaxisis0.4)
Fora100‐HzinputsignalwithanAmplitudeof10‐Vpeaktopeak,a
runningaverageoutputsa100‐Hzsignalwithanamplitudeof7.57‐V
peaktopeak.
There is also a phase shift, or delay, in the AvgRun() output. The formula for
calculating the delay, in number of samples, is:
Delayinsamples=(N‐1)/2
Note N = Number of points in running average)
To calculate the delay in time, multiply the result from the above equation by the
period at which the running average is executed (usually the scan period):
Delayintime=(scanperiod)(N‐1)/2
For the example above, the delay is:
Delayintime=(1ms)(4‐1)/2=1.5ms
Example:
Actualtestusinganaccelerometermountedonabeamwhoseresonant
frequencyisabout36Hz.Themeasurementperiodwas2ms.The
runningaveragedurationwas20ms(fre
quencyof50Hz),sothe
normalizedresonantfrequencyis,
36/50=0.72,SIN(0.72π)/(0.72π)=0.34.
Therecordedamplitudeforthisexampleshouldbeabout1/3ofthe
input‐signalamplitude.Aprogramwaswrittenwithtwostored
variables:Accel2andAccel2RA.Therawme
asurementwasstoredin
Accel2,whileAccel2RAwastheresultofperformingarunningaverage
ontheAccel2variable.Bothvalueswerestoredatarateof500Hz.
FigureRunning‐AverageSignalAttenuation
(p.273)showthetwovalues
plottedinasinglegraphtoillustratetheattenuation(therunning‐
averagevaluehastheloweramplitude).
Theresultantdelay(delayintime)=(Scanrate)(N‐1)/2=2ms(10‐1)/2=
9ms.Thisisabout1/3oftheinput‐signalperiod.
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