
Appendix B. Processing Time Limitations
Example 3
Given
: N = number of channels measured
F = Frequency of input signal, kHz
Function = frequency (Function 2)
Output Option = XXXX with specified sampling interval, S
Find
: Sampling interval, S, such that the number of unprocessed events is ≤
8000
Solution
: The interval required to process 8000 events after the sampling
interval is T
t
-S, therefore;
(T
t
-S)*F*N≤8000
S≥T
t
-(8000/(F*N))
S≥(0.511*S+E
t
*(.034+.010*N)+0.015*E
2
)
-(8000/(F*N))
Note: E
2
= E
t
= N*F*S
S≤8000/[F*N((0.511+N*F*(0.49 +.01*N))-1)]
Results for the above example are presented in Table 3, Section 5.4.1
B-3
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